For the following reaction, calculate how many moles of no2 forms when 0.356 moles of the reactant completely reacts.
2 n2o5g→4 no2g+o2g

0.712 mol of NO₂ are formed .

Explanation:

For the reaction , given in the question ,

2 N₂O₅ ( g )  →  4 NO₂ ( g ) + O₂ ( g )

From the above balanced reaction ,

2 mol of N₂O₅  reacts to give 4 mol of NO₂

Applying unitary method ,

1 mol of N₂O₅  reacts to give 4 / 2 mol of NO₂

From the question , 0.356 mol of N₂O₅ are reacted ,

now, using the above equation , to calculate the moles of the NO₂ , as follow -

Since ,

1 mol of N₂O₅  reacts to give 4 / 2 mol of NO₂

0.356 mol of N₂O₅  reacts to give 4 / 2 * 0.356 mol of NO₂

Calculating ,

0.712 mol of NO₂ are formed .

the answer is barium and copper bromide