To indicate the ph of a substance, one can use a dye that is both an acid and that appears as different colors in its protonated and deprotonated forms. suppose that you have a 0.001 m solution of a dye with a pka of 7.2. from the color, the concentration of the protonated form, ha, is 0.0002 m. assume that the remainder of the dye is in the deprotonated form, a−. what is the ph of the solution? give your answer to one decimal place. g

The pH of the solution is 7.8

Explanation:

The concentration of the solution is 0.001M and  the dye could be in its protonated and deprotonated forms. If the concentration of the protonated form [HA] is 0.0002 M the concentration of the deprotonated form will be the subtraction between the concentration of the bye and the concentration of the protonated form:

[A-] = 0.001M - 0.0002M = 0.0008M

Also, the Henderson-Hasselbalch equation is

this equation shows the dependency between the pH of the solution, the pKa and the concentration of the protonated and deprotonated forms. Thus, replacing in the equation

jdjxnbfb

explanation:

jjfnc fdnxnxx