Afecl3 solution is 0.175 m. how many ml of a 0.175 m fecl3 solution are needed to make 450. ml of a solution that is 0.300 m in cl- ion?

There is 257 mL of a 0.175 M FeCl3 solution needed.

Explanation:

Step 1: Data given

Fecl3 → Fe3+ + 3Cl-

This means that for 1 mole Fecl3 consumed, there is produced 1 mole of Fe3+ and 3 moles of Cl-

The FeCl3 solution has a molarity of 0.175 M

The molarity of the Cl- ion is 0.300 M

The solution has a volume of 450 ml = 0.450 L

Step 2:  Calculate the volume

M1V1 = M2V2

with M1 = 0.175*3 = 0.525 M

with V1 = TO BE DETERMINED

with M2 = 0.300 M

with V2 = 450 mL = 0.450 L

0.525 M * V1 = 0.300 M * 0.450 L

V1 = 0.135 / 0.525 M = 0.257 L = 257 mL

There is 257 mL of a 0.175 M FeCl3 solution needed.

it's c. elements are placed in rows based on how may valencies electrons have.

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