Asemipermeable membrane is placed between the following solutions. which solution will decrease in volume? solution a: 1.31% (m/v) starch solution b: 7.48% (m/v) starch 2.a semipermeable membrane is placed between the following solutions. which solution will increase in volume? solution c: 6.75% nacl solution d: 11.7% nacl

Are you in flvs, if so im prettyb sure if yo look on page 3 of lesson 1.04 it tells you the answer.

Explanation:

1. The volume of solution A (1.31%) will decrease.

2. The volume of solution D (11.7%) will increase.

Explanation:

1. If two solutions are separated by a semipermeable membrane, the water molecules will move through the membrane starting from the solution that has the low concentration of the solute towards the solution that has a high concentration of the solute. Therefore, if solution A has 1.31% starch and solution B has 7.48% starch, it can be seen that solution B has a higher concentration. This is why the water molecules will move from Solution A to Solution B.

2. Like exercise 1, solution C has a concentration of 6.75% NaCl and solution D has a concentration of 11.7% NaCl. Therefore, with solution D having a higher concentration, the water molecules will move from solution to solution D.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

answer; capital earns interest; entrepreneurship receives a profit or incurs a loss;