One container of tumsr costs 4.00 dollars. each container has eighty 1.00 g tablets. assume each tumsr is 40.0 percent caco₃ by mass. using only tumsr, you are required to neutralize 0.500 l of 0.400 m hcl. how much does this cost? assume you are able to purchase individual tablets. express your answer in dollars.

1.25 dollars.

Explanation:

The balanced reaction will be

mole ratio of and HCl is 1 : 2

mole of HCl will be as

0.500 L HCl × 0.4 mol/L = 0.2 mol HCl

moles of will be as

0.2 mole HCl × 1 mol mol HCl = 0.1 mol

mass of will be calculated as :

0.1 mol × 100.1 g / 1 mol = 10.01 g

Now 40.0% = = 0.4

mass of / (80 tablets × 1 g /tablets × 0.4 = number of containers

= 0.3128125 (number of containers)

Cost = number of containers × $4.00

        = 0.3128125 × 4.00

       =  $1.25

Cost would be $1.25.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g