Benzene has a heat of vaporization of 30.72 kj/mol and a normal boiling point of 80.1°c. at what temperature does benzene boil when the external pressure is 445 torr?

Explanation:

The given data is as follows.

            = = (80 + 273) = 353 K

  Atmospheric pressure = 445 torr

   Heat of vaporization = 30.72 kJ/mol =

                                      = 30720 J/mol

Now, according to Clausius-Clapereryon equation,

Putting the given values into the above equation as follows.

                   -0.5352 =                  

                    = 0.002977

                      = 335.909 K

or,                             =

                                =

Thus, we can conclude that benzene boils at when the external pressure is 445 torr.

the atomic mass is the bottom number on the element.

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