Enter your answer in the provided box. calcium hydroxide may be used to neutralize (completely react with) aqueous hydrochloric acid. calculate the number of g of hydrochloric acid that would be neutralized by 0.685 mol of solid calcium hydroxide. g hci

49.95 g of HCl

Explanation:

Let's formulate the chemical equation involved in the process:

Ca(OH)2 + 2 HCl → CaCl2 + 2 H2O

This means that we need 1 mole of Calcium hydroxide to neutralize 2 moles of hydrochloric acid. From this, we calculate the quantity of HCl moles that would be neutralized by 0.685 moles of Ca(OH)2

1 mole Ca(OH)2 2 moles HCl

0.685 moles Ca(OH)2 x = 1.37 moles HCl

Now that we know the quantity of HCl moles that would react, let's calculate the quantity of grams this moles represent:

1 mole of HCl 36.46094 g

1.37 moles x = 49.95 g of HCl

2b2t

explanation:

2b2t