You are given a protein solution with a concentration of 0.15 mg/ml.

iii. if the molecular weight of the protein is 22,000 da, express its initial concentration in moles/liter, micromoles/ml, and micromoles/microliters. if we want 20 micromoles of proteins for a reaction, what volume do we need to prepare?

We need  2.933 L of 0.15 mg /mL of protein solution.

Explanation:

Concentration of given solution

1 mg = 0.001 g , 1 mL = 0.001 L

Molecular weight of protein = 22,000 Da =22,000 g/mol

Initial concentration in moles/liter:

Initial concentration in micromoles/mL :

1 L = 1000 mL

Initial concentration in micromoles/microLiter :

1 L = 1000,000 μL

Moles of protein required = 20 μmoles

n(Moles)=C(concentration) × V(Volume of solution)

We need  2.933 L of 0.15 mg /mL of protein solution.

it is b that is the answer.