The nonvolatile, nonelectrolyte chlorophyll , c55h72mgn4o5 (893.5 g/mol), is soluble in diethyl ether ch3ch2och2ch3.

how many grams of chlorophyll are needed to generate an osmotic pressure of 1.19 atm when dissolved in 258 ml of a diethyl ether solution at 298 k.

? grams chlorophyll

The grams of chlorophyll you need are 11,1 g

Explanation:

Osmotic pressure is the minimum pressure that you needs to be apply to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. The formula of osmotic pressure  is:

π = M×R×T

Where:

M is molar concentration of dissolved species (units of mol/L).

R is ideal gas constant (0.08206 L atm mol⁻¹ K⁻¹, ).

T is the temperature on the Kelvin scale.

In the problem you have:

1,19 atm = M×0,08206 L atm mol⁻¹ K⁻¹×298K

M = 0,048 M

Thus, the grams of chlorophyll you need are:

0,048 × 0,258 L × = 11,1 g

I hope it helps!

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a electronegativity decreases beacuse the size of nucleus is bigger.