You need to make an aqueous solution of 0.217 m zinc fluoride for an experiment in lab, using a 250 ml volumetric flask. how much solid zinc fluoride should you add?

Explanation:

The given data is as follows.

           Volume = 250 mL,       Molarity = 0.217 M

Molar mass of is 103.406 g/mol.

As molarity is the number of moles of solute present in liter of solution.

As, it is given that molarity is 0.217 M. This means that 0.217 moles are present in 1 liter of solution.

Therefore, number of moles present in 250 mL are calculated as follows.

              = 0.05425 mol

Since, number of moles equal mass divided by molar mass. Therefore, calculate the mass of as follows.

                      Mass = no. of moles × Molar mass

                                =

                                = 5.61 g

Thus, we can conclude that mass of zinc fluoride is 5.61 g.