What partial pressure of c2h4 gas (in mm hg) is required to maintain a solubility of 4.92×10-2 g/l in water at 25 °c? kh for c2h4 at 25 °c is 4.78×10-3 mol/l·atm.

The partial pressure of is 281 mmHg

Explanation:

We are given:

Solubility of ethene gas =

To convert this solubility into mol/L, we divide the given solubility by the molar mass of the gas, which is 28 g/mol

To calculate the molar solubility, we use the equation given by Henry's law, which is:

where,

= Henry's constant =

= molar solubility of ethene gas =

Putting values in above equation, we get:

Converting this into mmHg, we use the conversion factor:

1 atm = 760 mmHg

So,

Hence, the partial pressure of is 281 mmHg

answer: lol

explanation:

lol