What is the de broglie wavelength of an electron traveling at 1.62×105 m/s ?

0.449  10^(-8)  meters

meters

Explanation:

Use the deBroglie equation for the wavelength (lambda):

where h stands for the Plank constant:

m stands for the mass of the electron:

and v is the given velocity:

Evaluating lambda for these values:

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

yes

explanation:

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