Liquid dimethyl disulfide (ch3ssch3) flows through a pipe with a mass flow rate of 86.0 g's. given that the density of dimethyl disulfide is 1.0625 g/cm, find: the molar flow rate in molimin: number mol/min the volumetric flow rate in l/hr.

Explanation:

Molar mass of is 94 g/mol. As it is known that number of moles is equal to mass of a substance divided by its molar mass.

Then, calculate the number of moles as follows.

     No. of moles = in 1 s

                           = 0.914 mol

So, in 60 sec number of moles will be equal to 0.914 x 60 = 54.89 mol/min.

Hence, the molar flow rate = 54.89 mol/min

Also, density is equal to mass of a substance divided by its volume.

                    Density =

                      Volume =

                                     =

                                     = 80.941

As, 80.941 of volume flows in 1 s . Therefore, flow of volume in 1 hour will be calculated as follows.

                 In 1 hr = 80.941

                            = 291388.24

Since, 1 = 0.001 L.

So,              291388.24

                            = 291.38824 L/hr

Thus, we can conclude that molar flow rate in mol/min is 54.89 mol/min and the volumetric flow rate in L/hr is 291.38824 L/hr.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2