Aliquid mixture contains water (h2o, mw = 18.0), ethanol (c2h5oh, mw = 46.0) and methanol (ch3oh, mw = 32.0). using two different analytical techniques to analyze the mixture, it was determined that the water mole fraction was 0.250 while the water mass fraction was 0.134. determine the mole fraction ethanol (c2h5oh) and the mole fraction methanol (ch3oh) in the solution. report the values to the correct number of significant figures.

Mole fraction of ethanol is 0.363.

Mole fraction of methanol is 0.387.

Explanation:

Mole fraction of water =

Mole fraction of ethanol =

Mole fraction of methanol =

Moles of water =

Moles of ethanol=

Moles of methanol=

Mass of the mixture = M

Mass of water,

Fraction of water by mass = 0.134

Mass of ethanol =

Mass of methanol =

..[1]

..[2]

On solving [1] and [2]:

Mole fraction of ethanol =

Mole fraction of methanol =

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b