Chemistry, 25.09.2019 00:10 FireFlight

What is the nuclear binding energy of he? mass of he nucleus 4.00150 amu mass of a proton 1.00728 amu 1.00866 amu mass of a neutron 2.9979*10 m/s speed of light 6.022x103 abogadro's number

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Answer from: jfif

Answer : The nuclear binding energy of He for one mole is $2.0\times 10^{12}J/mol$

Explanation :

The isotopic representation of He : $_{2}^{4}\textrm{He}$

Atomic number = Number of protons = 2

Mass number = 4

Number of neutrons = Mass number - Atomic number = 4 - 2 = 2

To calculate the mass defect of the nucleus, we use the equation:

$\Delta m=[(n_p\times m_p)+(n_n\times m_n)+]-M$

where,

n_p = number of protons = 2

m_p = mass of one proton = 1.00728 amu

n_n = number of neutrons = 2

m_n = mass of one neutron = 1.00866 amu

M = Nuclear mass number = 4.00150 amu

Putting values in above equation, we get:

$\Delta m=[(2\times 1.00728)+(2\times 1.00866)]-[4.00150]\\\\\Delta m=0.03038amu$

Now converting the value of amu into kilograms, we use the conversion factor:

$1amu=1.66\times 10^{-27}kg$

So, $0.03038amu=0.03038\times 1.66\times 10^{-27}kg=0.0504\times 10^{-27}kg$

To calculate the equivalent energy, we use the equation:

$E=\Delta mc^2$

E = nuclear binding energy = ?

$\Delta m$ = mass change = $0.0504\times 10^{-27}kg$

c = speed of light = $3\times 10^8m/s$

Putting values in above equation, we get:

$E=(0.0504\times 10^{-27}kg)\times (3.0\times 10^8m/s)^2\\\\E=4\times 10^{-12}J$

Nuclear binding energy for one mole is:

$E=(4.0\times 10^{-12}J)\times (6.022\times 10^{23}mol^{-1})=2.0\times 10^{12}J/mol$

Therefore, the nuclear binding energy of He for one mole is $2.0\times 10^{12}J/mol$

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

Answer from: Quest

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. $hbr$ completely dissociates to $h^+$ and $br-$ ions. a is incorrect because $h_2s$ does not fully ionize to $h^+$ and $hs^-$ ions and some remain as the compound $h_2s$ . c and d are incorrect because, $li_2o$ and $libr$ do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise, if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both $li_2o$ and $libr$ have a complete octet so can not accept any electrons which disqualifies them as acids.

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What is the nuclear binding energy of he? mass of he nucleus 4.00150 amu mass of a proton 1.00728 a...

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