Find the work done using data from the pv plot for an isothermal system.
p1= 100 kpa, p2= 300 kpa
v1= 25 m^3 , v2= 10 m^3
b.) is the work done by the system or on the system?

W = - 500 KJ

∴ the work is done on the system

Explanation:

isothermal system:

∴ ΔU = 0; ⇒ Q = W

∴ W = P1V1 -P2V2

⇒ W = ((100KPa)*(25m³)) - ((300KPa)*(10m³))

⇒ W = 2500KPa.m³ - 3000KPa,m³

⇒ W = - 500 KPa.m³ = - 500 KJ

∴ W (-) the work is done on the system

the answer is 0.42 is that is an option. this question provides no info