Estimate the density of a mixture of50% acetone and 50% water by volume additivity

892 grams/liter

Explanation:

in order to calcuñate this you jus have to add the percentage of the volume of both water has a density of 1000 gms/liter or 1 gram/mililter and the acetone is 784 g/l so if that is 50%-50% you multiply that by .5 and you add them up and get the density of the mix of them both:

1000*,5= 500g/l

784*,5=392 g/l

500+392=892g/l

So the density of a mixture 50-50 of water and acetone would be 892 g/l

answer; i believe the correct answer is (solid gold);

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%