Hemoglobin is a large protein molecule that is responsible for carrying oxygen through the blood. iron ions are a relatively small component of hemoglobin. there are four fe2+ions that are part of the much larger hemoglobin structure. in a single red blood cell there are 2.50x108molecules of hemoglobin. if a single fe2+ion has an atomic radius of 75.1 pm and a redblood cell has a volume of 95 μm3, what percentage of the total red blood cell volume is taken up by fe2+ions?

The percentage of volume taken by iron(II) in the blood cell is 0.0019%.

Explanation:

Radius of iron(II) ions ,r= 75.1 pm =

1 pm = 10^{-6} μm

Volume of sphere  =

Volume of single iron(II) ion = V

Number of iron(II) ions in one hemoglobin structure = 4

Number of hemoglobin structure in blood cell = molecules

Then number of iron (II) ions in molecules of hemoglobin:

Volume of ions of iron =

Volume of the  hemoglobin structure,V' =

Percentage volume of iron (II) ions in a single blood cell:

=

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