What volume in ml of a 0.121 m sodium hydroxide solution is required to reach the equivalence point in the complete titration of a 10.0 ml sample of a 0.102 m sulfuric acid? (hint: write the equation out)

8.42 mL

Explanation:

For the equivalence point for the reaction of an acid and base , is given by the following formula -

M₁V₁ = M₂V₂

where ,

M₁ = acid's concentration ,

V₁ = acid's volume ,

M₂ = base's concentration ,

V₂ = base's volume .

from , the question ,

M₁  = 0.102 M ( acid )

V₁ = 10.0 mL  ( acid )

M₂ = 0.121 M ( base )

V₂ = ?

To calculate the volume of the base , the above formula is used and the respective values are substituted , as follow -

M₁V₁ = M₂V₂

0.102 M *  10.0 mL = 0.121 M * V₂  

V₂  = 1.02 / 0.121 = 8.42 mL

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.