The antacid component of tumsr is calcium carbonate. assume tumsr is 40.0 percent caco3 by mass. if we have 400. mg of tumsr how many ml of 0.100 m hcl can we neutralize? express your answer in ml.

31.9724 mL

Explanation:

The given antacid, Tumsr contains 40% of by mass.

Given mass of Tusmr = 400 mg

Mass of =

Also, 1 mg = 0.001 g

Mass of in Tusmr = 0.16 g

Molar mass of = 100.0869 g/mol

Moles = Mass / Molar mass = 0.16 g / 100.0869 g/mol = 15.9862 × 10⁻⁴ moles

Considering the reaction:

1 mole of react with 2 moles of HCl

15.9862 × 10⁻⁴ moles of react with 2*15.9862 × 10⁻⁴ moles of HCl

Moles of HCl = 31.9724 × 10⁻⁴ moles

Considering:

Or,

Given :

For HCl :

Molarity = 0.100 M

Let, Volume = x mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = x ×10⁻³ L

Moles of HCl =  31.9724 × 10⁻⁴

Volume = x = 31.9724 mL

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