Calculate each of the following quantities.
(a) mass in kilograms of 3.7 x 1020 molecules of no2

The answer to your question is:  0.028 kg of NO2

Explanation:

Data

3.7 x 10²⁰ molecules of NO2 in kg

MW of NO2 = 14 + (16 x 2) = 14 + 32 = 46 kg

                   1 mol of NO2  6.023 x 10 ²³ molecules

                   x                     3.7 x 10²⁰ molecules

                   x = 3.7 x 10²⁰ x 1 / 6.023 x 10 ²³

                   x = 0.00061 mol

                 1 mol of NO2  46 kg of NO2

                 0.00061 mol        x

                 x = 0.00061 x 46/1

                x = 0.028 kg of NO2

2b2t

explanation:

2b2t