In which of the following reactions would you expect the orientation factor to be least important in leading to reaction: co+o→co2 or h+f→hf? match the words in the left column to the appropriate blanks in the sentence on the right. co+o→co2c o + o rightarrow c o subscript2 termolecular unimolecular monatomic diatomic h+f→hfh + f rightarrow h f the orientation factor is less important in the orientation factor is less important in blank because the reactants are blank and spherical (nondirectional); all collision orientations are equally effective. because the reactants are the orientation factor is less important in blank because the reactants are blank and spherical (nondirectional); all collision orientations are equally effective. and spherical (nondirectional); all collision orientations are equally effective.

kdkdkrnmcnc

explanation:

wisjndnfnnjjdjdjxn

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

since electrons are negative the answer is neagtaive

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.