It is possible to predict the equilibrium constant of a reaction by combining two or more reactions for which the value of k is known. when combining equilibrium constants, it is important to note the following: when a reaction is reversed, its k value is inverted; that is, kreverse=1/kforward. when the coefficients of a reaction are multiplied by a factor, the k value is raised to the power of that factor. when reactions are added, their k values are multiplied. part a determine the value of the equilibrium constant, kgoal, for the reaction c(s)+12o2(g)+h2(g)⇌12ch3oh(g)+12co( g), kgoal=? by making use of the following information: 1. co2(g)+3h2(g)⇌ch3oh(g)+h2o(g), k1 = 1.40×102 2. co(g)+h2o(g)⇌co2(g)+h2(g), k2 = 1.00×105 3. 2c(s)+o2(g)⇌2co(g), k3 = 2.10×1047 express your answer numerically. view available hint(s) kgoal = nothing part b determine the equilibrium constant, kgoal, for the reaction 4pcl5(g)⇌p4(s)+10cl2(g), kgoal=? by making use of the following information: p4(s)+6cl2(g)⇌4pcl3(g), k1=2.00×1019 pcl5(g)⇌pcl3(g)+cl2(g), k2=1.13×10−2 express your answer numerically.

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.

more infor would

a lot