When 282 gr of glycine are dissolved in 950 gr of a certain mystery liquid, the freezing point of the solution is 8.2 c less than the freezing point of pure. calculate the mass of iron(iii) chloride that must be dissolved in the same mass of to produce the same depression in freezing point. the van't hoff factor for iron(iii) chloride in x. be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.

Explanation:

Depression in freezing point is given by:

= Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like glycine)

= freezing point constant = ?

m= molality

Weight of solvent = 950 g = 0.95 kg

Molar mass of glycine = 75.07 g/mol

Mass of glycine added = 282 g

Thus freezing point constant is

2)

= Depression in freezing point

i= vant hoff factor = 4 (for )

= freezing point constant =

m= molality  

Weight of solvent = 950 g = 0.95 kg

Molar mass of = 162.2 g/mol

Mass of   added = ?

Thus mass of iron(III) chloride that must be dissolved in the same mass of to produce the same depression in freezing point is