The decomposition of n2o5 in carbon tetrachloride proceeds as follows: 2n2o5→4no2+o2 the rate law is first order in n2o5. at 64 ∘c the rate constant is 4.82×10−3s−1. you may want to reference (pages 576 - 581) section 14.3 while completing this problem. part a which of the following is the rate law for this reaction? which of the following is the rate law for this reaction? rate=4.82×10−3s−1[n2o5]2 rate=2.41×10−3s−1[n2o5] rate=4.82×10−3s−1[n2o5] rate=9.64×10−3s−1[n2o5]

r = 2.41 E-3 s-1 [ N2O5 ]

Explanation:

∴ k = 4.82 E-3 s-1

⇒ r =  k [ N2O5 ]/2

⇒ r = (4.82 E-3 s-1 [ N2O5 ])/2

⇒ r = 2.41 E-3 s-1 [ N2O5 ]

rate = 4.82x10⁻³*[N₂O₅]

Explanation:

The rate of a reaction represents how much moles of the reactant is disappearing along the time, and for a reaction with only one reactant, it can be calculated by:

rate = k*[reactant]ⁿ

Where k is the rate constant, [reactant] is the initial concentration of the reactant, and n is the order of the reaction, which is determined by experiments. So, if the rate law is first order, n = 1:

rate = 4.82x10⁻³*[N₂O₅]

8 carbon atoms forming single bonds with 18 hydrogen atoms; a triple bond exists between the third and fourth carbon atom from the right

explanation:

smooth muscle is composed of involuntary muscles found within the walls of organs and structures such as the esophagus, stomach, intestines, and blood vessels. those muscles push materials like food or blood through organs. unlike skeletal muscle, smooth muscle can never be under your control.