Asolution of nacl(aq)nacl(aq) is added slowly to a solution of lead nitrate, pb(no3)2(aq)pb(no3)2(aq) , until no further precipitation occurs. the precipitate is collected by filtration, dried, and weighed. a total of 13.25 g pbcl2(s)13.25 g pbcl2(s) is obtained from 200.0 ml200.0 ml of the original solution. calculate the molarity of the pb(no3)2(aq)pb(no3)2(aq) solution.

The molarity of the Pb(NO3)2 solution is 0.24 M

Explanation:

Assuming there was no loss during filtration, we can calculated amount of moles Pb(NO3)2 from the 13.25 g of PbCl2 ussing molar mass of  PbCl2

13.25 g / 278.1 g = 0.04 moles of PbCl2

According balanced equation 2NaCl + Pb(NO3)2 = 2NaNO3 + PbCl2, 1 mol of Pb(NO3)2 produces 1 mol of PbCl2. So, 0.04 moles of Pb(NO3)2 produces PbCl2

Molarity is = moles of solute/volumen of solution (L)=0.04/0.2= 0.24

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