Three solutions 39.0 ml of 0.2 m kno₃; 59.0 ml of 0.9 m ca(no₃)₂; and 63.0 ml of 0.345 m kcl were poured together to make one new solution. what is the concentration of cl⁻ after mixing? answer in units of mol/l.

[Cl⁻] = 0.135 M

Explanation:

The concentration of Cl⁻ is equal to the total moles of Cl⁻ divided by the total volume:

C = n/V

All of the moles of Cl⁻ come from dissociation of the KCl:

KCl ⇒ K⁺ + Cl⁻

We will calculate the moles of Cl⁻ based on the amount of KCl added by using the molar ratio of 1:1.

(0.345 mol/L)(63.0 mL) = (21.735 mmol KCl)(Cl⁻/KCl) = 21.735 mmol Cl⁻

Extra significant figure are kept to avoid round-off errors.

Now we can calculate the total volume, which is the sum of the volume of the three solutions added:

(39.0 mL) + (59.0 mL) + (63.0 mL) = 161.0 mL

Finally, we calculate the concentration of Cl⁻

[Cl⁻] = (21.735 mmol) / (161.0 mL) = 0.135 M

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.