Asolution contains one or more of the following ions: ag+, ca2+, and fe2+. when sodium chloride is added to the solution, no precipitate forms. when sodium sulfate is added to the solution, a white precipitate forms. then, the precipitate is filtered off and sodium carbonate is added to the remaining solution, and a precipitate forms. which of the ions were present in the original solution? select all that apply.

the ion present in the original solution is Ca2+

Explanation:

Precipitation reactions occur when cations and anions in aqueous solution combine to form an insoluble ionic solid called a precipitate.

Step1 : If we add Nacl to the solution, there is no precipitate formed

⇒The only possible ion that can form a precipate with Cl- is Ag+; since there is no precipitate formed, Ag+ is not present

Step2 : If we add Na2SO4 to the solution, a white precipitate is formed

The possible ions to bind at SO42- are Ca2+ and Fe2+

But the white precipitate formed, points in the direction of Ca2+

⇒This means calcium is present

Step3 : If we add Na2CO3 to the filtered solution, there is a precipate formed

Ca2+ will bind also with CO32- and form a precipitate

So the ion present in the original solution is Ca2+

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

im pretty sure its b