If a solution containing 34.23 g of mercury(ii) acetate is allowed to react completely with a solution containing 5.102 g of sodium sulfide, how many grams of solid precipitate will be formed? mass: 15.21 g how many grams of the reactant in excess will remain after the reaction? mass: 13.39 g assuming complete precipitation, how many moles of each ion remain in solution? if an ion is no longer in solution, enter a zero (0) for the number of moles. hg2+ :

Na2S is the limiting reactant, 0.06537 mole will be fully consumed.  

mercury(II) acetate is in excess, there remains 0.04203 ( 13.39g)

There will be formed 0.06537 mole HgS (15.21g) and 0.13074 mole of N a C 2 H 3 O 2 (10.725g)

Explanation:

Step 1 : Balance the reaction

C 4 H 6 O 4 H g  +  N a 2 S  → H g S  +  2 N a C 2 H 3 O 2

First we have to find which is the limiting and which is the excess reagents.

This we do by calculating number  of moles

We see that for each 1 mole C 4 H 6 O 4 H g reacting, there is 1 mole of Na2s reacting and there is be formed 1 mole of HgS but 2 mole of 2 N a C 2 H 3 O 2

Step 2 : Calculating moles

mole = mass / Molar mass

⇒ mole C 4 H 6 O 4 H g = 34.23g / / mole =318.6780g 0.1074 mole

⇒ mole Na2S = 5.102g / 78.0452g/mole = 0.06537 mole

The limiting reactant is Na2S, which will be fully consumed after HgS and 2 N a C 2 H 3 O 2 is formed.

C 4 H 6 O 4 H g is the reactant in excess, after being consumed there will still be left.

⇒mole HgS : there will be produced 0.06537 mole HgS

⇒mole  N a C 2 H 3 O 2 : there will produced 0.13074 mole N a C 2 H 3 O 2

This means there will formed: 0.06537mole x 232.66g/mole = 15.2089842g  ≈15.21g HgS formed

Since there is consumed 0.06537 mole C 4 H 6 O 4 H g, there still remain: 0.1074- 0.06537 mole =0.04203 mole C 4 H 6 O 4 H g

mass C 4 H 6 O 4 H g = 0.04203 mole C 4 H 6 O 4 H g * 318.6780g/mole = 13.3940g ≈ 13.39g

So for C4H6O4Hg there remain 0.04203 mole in solution, which is 13.39g

Na2S is completely consumed, so there remain 0 moles

There got formed 0.06537 mole of HgS or 15.21g

and also 0.13074 mole of N a C 2 H 3 O 2 or  10.725g

fire could start, buildings collapsing, and ash falling from the sky.

explanation:

this is because the buildings or plants could catch on fire and the buildings would most likely collapse. lastly ash would fall because all the burning would cause ash to fall from the sky.

hope this .