Metals often form several cations with different charges. cerium, for example, forms ce3+ and ce4+ ions, and thallium forms tl+ and tl3+ ions. cerium and thallium ions react as follows: 2ce4+(aq)+tl+(aq)→2ce3+(aq)+tl3+(aq ) this reaction is very slow and is thought to occur in a single elementary step. the reaction is catalyzed by the addition of mn2+(aq) according to the following mechanism: ce4+(aq)+mn2+(aq)ce4+(aq)+mn3+(aq)m n4+(aq)+tl+(aq)→→ →ce3+(aq)+mn3+(aq)ce3+(aq)+mn4+(aq) mn2+(aq)+tl3+(aq) part a what is the rate law for the uncatalyzed reaction?

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-