Certain metal oxide has the formula mo where m denotes the metal. a 73.35−g sample of the compound is strongly heated in an atmosphere of hydrogen to remove oxygen as water molecules. at the end, 64.21 g of the metal is left over. if o has an atomic mass of 16.00 amu, calculate the atomic mass of m and identify the element.

atomic mass 112.4 and Cadmium (Cd)

Explanation:

You have 73.35 g of MO.

After the reaction the O is removed and you only have M which the mass is 64.21 g.

With that you can calculate the mass of O removed:

Mass of O = 9.14 g

Mass = AM * moles ; (AM : Atomic Mass)

9.14 = 16 * moles

moles = 9.14 / 16

moles = 0.57125

The formula of the metal oxide is MO, meaning it has 1 mole of M per mole of O. 73.35 had 0.57125 moles of O, then it also had 0.57125 moles of M, and the remaining mass of 64.21 g represents those moles

Mass = AM * moles ; (AM : Atomic Mass)

64.21 = AM * 0.57125

AM = 64.21/0.57125 = 112.4 amu

The metal with an atomic mass of 112.4 is Cadmium (Cd), therefore the metal oxide is CdO

a boiling water reactor does not boil the water. a pressurized water reactor boils the water faster. a pressurized water reactor is heated directly by the core. a pressurized water reactor does not use fission.

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error