On his first day of school, kareem found the high temperature in degrees fahrenheit to be 76.1°. he plans to use the function c of f = five-ninths (f minus 32) to convert this temperature from degrees fahrenheit to degrees celsius. what does c(76.1) represent? a. the temperature of 76.1 degrees fahrenheit converted to degrees celsius
b. the temperature of 76.1 degrees celsius converted to degrees fahrenheit
c. the amount of time it takes a temperature of 76.1 degrees fahrenheit to be converted to 32 degrees celsius
d. the amount of time it takes a temperature of 76.1 degrees celsius to be converted to 32 degrees fahrenheit

a. the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius

Explanation:

The function is

C(F) =

Where C is the temperature in ºC, and F is the temperature in ºF. So, when we replace F for the temperature, we can calculate this temperature in degrees Celsius; and when we replace C, we calculate the temperature in degrees Fahrenheit.

In the expression C(76.1), F was replaced by 76.1, so we will calculate the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius.

A. the temperature of 76.1 degrees Fahrenheit converted to degrees Celsius

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

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