An earthquake with a magnitude of 6.3 is 25 times as intense as an aftershock that occurs 8 hours later. what is the magnitude of the aftershock? round your answer to one decimal place

Magnitude of the aftershock = 0.3

Explanation:

Based on the information in the problem, an expression can be written that relates the magnitude of the earthquake (M₁) with the magnitude of the aftershock (M₂):

M₁ = 25M₂

We can then solve for M₂ and substitute in the values in the problem:

M₂ = M₁ / 25 = 6.3 / 25 = 0.3

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied