Consider these compounds:
a. pbf2
b. ag2so3
c. nico3
d. agcl
complete the following statements by entering the letter(s) corresponding to the correct compound(s). (if more than one compound fits the description, include all the relevant compounds by writing your answer as a string of characters without punctuation, e. g, abc.)
without doing any calculations it is possible to determine that silver chromate is more soluble , and silver chromate is less soluble .
it is not possible to determine whether silver chromate is more or less soluble by simply comparing kspvalues.

Without doing any calculations it is possible to determine that silver chromate is more soluble than C,D , and silver chromate is less soluble than none .

It is not possible to determine whether silver chromate is more or less soluble than A,B by simply comparing Kspvalues

Explanation:

For this kind of question you need to obtain the balanced equation for the solubility, first, you will write the dissociation equation for every molecule, obtaining the ions in which it dissociates. Then you substitute in the Kps equation

Considering the corresponding stoichiometry you'll substitute in your dissociation equations as follow.

IIn this case, the silver chromate has a Kps of , same as the compound in options A and B, comparing these numbers you can't determine which one is bigger. Finally, options C and D have a kps of , this value is smaller than silver chromate's kps.

I hope you find this information useful! good luck!

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.