If 72.1 ml of 0.543 m h2so4 completely titrates 39.0 ml of koh solution, what is the molarity of the koh solution? a. 0.317 m b. 0.502 m c. 1.00 m d. 2.01 m

The correct answer is Option  d.

Explanation:

To calculate the molarity of base, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is KOH

We are given:

Putting values in above equation, we get:

Hence, the correct answer is Option d.

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