the oxidation of the sugar glucose, c6h12o6, is described by the following equation. c6h12o6(s) + 6 o2(g) → 6 co2(g) + 6 h2o(l) δh = −2802.5 kj/mol the metabolism of glucose gives the same products, although the glucose reacts with oxygen in a series of steps in the body.
(a) how much heat in kilojoules can be produced by the metabolism of 18.1 g of glucose?
(b) how many calories can be produced by the metabolism of 18.1 g of glucose?

For a: The amount of heat produced for given amount of glucose is -283.05 kJ

For b: The amount of heat produced for given amount of glucose is -67648.9 Cal

Explanation:

To calculate the number of moles, we use the equation:

Given mass of glucose = 18.1 g

Molar mass of glucose = 180.16 g/mol

Putting values in above equation, we get:

The given chemical reaction follows:

By Stoichiometry of the reaction:

When 1 mole of glucose is reacted, the amount of heat released is 2802.5 kJ

So, when 0.101 moles of glucose is reacted, the amount of heat released is

Hence, the amount of heat produced for given amount of glucose is -283.05 kJ

To convert the heat produced in kilo joules to calories, we use the conversion factor:

1 kJ = 239 Cal

So,

Hence, the amount of heat produced for given amount of glucose is -67648.9 Cal

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