What is the theoretical yield of bismuth when 198 g of bi2o3 reacts with excess carbon as shown below? bi2o3 c(s)> bi(s) + co(g) (not balanced)

179.4306 g

Explanation:

Given that:

Mass of = 198 g

Molar mass of = 465.96 g/mol

The formula for the calculation of moles is shown below:

Thus,

From the balanced reaction,

1 mole of on reaction produces 2 moles of bismuth

So,

0.4293 mole of on reaction produces 2 × 0.4293 moles of bismuth

Moles of bismuth = 0.8586 moles

Molar mass of bismuth = 208.9804 g/mol

So, mass of bismuth = Moles × Molar mass = 0.8586 × 208.9804 g = 179.4306 g

lol for the pointsss