Answers: 3
.![pOH=-\log[OH^-]](/tpl/images/0231/1728/fe336.png)
![2.40=-\log[OH^-]](/tpl/images/0231/1728/df4f9.png)
![[OH^-]=0.003981 M](/tpl/images/0231/1728/10832.png)
![pH=-\log[H_3O^+]](/tpl/images/0231/1728/a23b5.png)
![11.6=-\log[H_3O^+]](/tpl/images/0231/1728/ac16c.png)
![[H_3O+]=2.5119\times 10^{-12} M](/tpl/images/0231/1728/799d3.png)
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The poh of an aqueous solution at 25°c was found to be 2.40. the ph of this solution is the hydroniu...
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