Determine the theoretical yield of p2o5, when 3.07 g of p reacts with 6.09 g of oxygen in the following chemical equation
4 p + 5 o2 > 2 p2o5

14.2 grams

Explanation:-

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

given mass of phosphorous (P) = 3.07 g

Molar mass of phosphorous (P) =  31 g/mol

Putting in the values we get:

given mass of oxygen = 6.09 g

Molar mass of oxygen =  32 g/mol

Putting in the values we get:

According to stoichiometry:

4 moles of phosphorous combine with 5 moles of oxygen

Thus 0.1 moles of phosphorous combine with = moles of oxygen

Thus phosphorous acts as limiting reagent as it limits the formation of product and oxygen is the excess reagent.

4 moles of phosphorous gives=  2 moles of

Thus 0.1 moles of phosphorous gives = moles of

mass of

Thus the theoretical yield of is 14.2 grams.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.