Ethylene enters a reversible, isothermal, steady-flow compressor at 1 bar and 280 k, and exits at 40 bar. find the required compressor work (kj/kmol) using the ideal gas equation of state.

Required compressor work W=8560.44  KJ/Kmol

Explanation:

Given that

Initial pressure = 1 bar

Final pressure = 40 bar

Process is isothermal and T=280 K

We know that ,work done in isothermal process given as

given taht gas is ideal so

P V =m R T

R for ethylene

R=0.296 KJ/kg.K

Now by putting the values

W= -305.73 KJ/kg

Negative sign indicates that work done on the system.

Required compressor work W=305.73 KJ/kg

Molar mass of ethylene M= 28 Kg/Kmol

So W= 305.73 x 28  KJ/Kmol

W=8560.44  KJ/Kmol

Required compressor work W=8560.44  KJ/Kmol

2b2t

explanation:

2b2t