Adilute aqueous solution of calcium hydroxide at 25°c reacts with gaseous hydrogen chloride via the following reaction +2h,0 2hcig) + ca(он), (аg, саcl, ag, r=oo r=oo if the hydrogen chloride enters the reactor at 90.0°c, and the solution exits at 25°c, how much heat must be removed for every mole of cacl2 produced? the heat of solution of ca(oh)2 is -1008.2 kj/mol, the heat of formation of ca(oh)2 is -985.65 kj/mol, the heat of solution of cacl2 is -875.07 kj/mol and the heat of formation of cacl2 is -797.46 kj/mol number kj/ mol

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

(b) which contains higher levels of vitamin b, oranges or spinach?

explanation:

you can eliminate a, c, and d because they are questions based on opinions.