Air of 97% relative humidity at 1 atm pressure and 311 k is to be cooled to 291 k, and fed into a plant at a rate of 8.5 m/s. (a) [12 points) calculate the rate in kg/min at which the water condenses. (b) (13 points calculate the cooling requirement in tons assuming that the enthalpy of water vapor is that of saturated steam at the same temperature and the enthalpy of dry air in kj/mol) as a function of temperature (in °c) is given by the equation h = 0.029 (t-25) data: saturation vapor pressure of water at 311 k = 6.54 x 102 atm saturation vapor pressure of water at 291 k = 2.04 x 102 atm enthalpy of saturated steam at 311 k=2570.8 kj/kg enthalpy of saturated steam at 291 k -2534.5 kj/kg enthalpy of liquid water at 291 k = 75.5 kj/kg one ton of cooling - 12,660 kj/hr