Problem page try again your answer is wrong. in addition to checking your math, check that you used the right data and did not round any intermediate calculations. a chemist prepares a solution of iron(ii) bromide by measuring out of iron(ii) bromide into a volumetric flask and filling the flask to the mark with water. calculate the concentration in of the chemist's iron(ii) bromide solution. round your answer to significant digits.

No. an alpha particle is a pair of protons and a pair of neutrons, i.e. a helium

Replicate prove reliability and validity

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

It is a product