Part a in a particular experiment at 300 ∘c, [no2] drops from 0.0138 to 0.00886 m in 374 s . the rate of disappearance of no2 for this period is m/s. in a particular experiment at 300 , drops from 0.0138 to 0.00886 in 374 . the rate of disappearance of for this period is . −6.06×10−5 6.60×10−6 7.57×104 2.64×10−5 1.32×10−5

The rate of disappearance of for this period is

Explanation:

Initial concentration of = x = 0.0138 M

Final concentration of = y = 0.00886 M

Time elapsed during change in concentration = Δt = 374 s

Change in concentration ,= y - x = 0.00886 - 0.0138 M = -0.00494 M

The rate of disappearance of for this period is:

the answer would be c

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