The equilibrium reaction below has the kc = 3.93. if the volume of the system at equilibrium is increased from 2.00 liters to 8.00 liters, how and for what reason will the equilibrium shift? be sure to calculate the value of the reaction quotient, q, and use this to confirm your answer.
co (g) + 3h2(g) -ch4(g) + h2o (g)

Q = 62.9

Q > Kc, so the reaction will proceed to the left so that Q takes the value of Kc.

Explanation:

Let's consider the following reaction.

CO(g) + 3 H₂(g) ⇄ CH₄(g) + H₂O(g)

The equilibrium constant (Kc) is:

If the volume is multiplied by 4 (2.00 L → 8.00 L), the concentrations will be divided by 4. The reaction quotient (Q) is:

Q > Kc, so the reaction will proceed to the left so that Q takes the value of Kc.

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter