Identify the isotope where a equals 49 and z equals 22.
a) indium-22
b) indium-27
c) indium-49
d) titanium-22
e) titanium-27
f) titanium-49
g) none of the choices are correct.

Titanium-49

Explanation:

A is the mass number and is equal to number of protons + number of neutrons.

Z is the atomic number and it is equal to number of protons and number of electrons.

Now the isotope will be recognized by the mass number which is 49 a.m.u. and the atomic number which is equal to 22. The isotope will be Titanium-49.

D) Titanium-22

Explanation:

Titanium is one of the transition metal elements. It is the 22nd element on the periodic table.

From the statement of the problem:

  A  is the mass number of the unknown atom which is 49. The mass number is the number of protons and neutrons in the nucleus of the atom.

   Z is the atomic number of the unknown atom which is 22. The atomic number is the number of protons in an atom. It is the same as the number of electrons for a neutral atom.

To identify the element, we simply use the atomic number because the periodic table of element is a function of the atomic number Therefore, the element with atomic number 22 on the periodic table is Titanium.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !