Calculate δhrxn for the following reaction: fe₂o₃(s)+3co(g)→2fe(s)+3co₂(g) use the following reactions and given δh′s. 2fe(s)+3/2o₂(g)→fe₂o₃(s), δh = -824.2 kj co(g)+1/2o₂(g)→co₂(g), δh = -282.7 kj

Answer : The enthalpy change of reaction is -23.9 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given final reaction is,

The intermediate balanced chemical reaction will be,

(1)    

(2)    

First we will reverse the reaction 1 and multiply equation 2 by 3 then adding both the equation, we get :

(1)    

(2)    

The expression for final enthalpy is,

Therefore, the enthalpy change of reaction is -23.9 kJ

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.