How do trans fats complicate the previous description of saturated and unsaturated fats?
a) trans fats are unsaturated because they have one or more double bonds, but their molecules are straight due to that they have been generated from newly synthesized saturated fats.
b) trans fats are unsaturated because they have one or more double bonds, but they have physical characteristics similar to saturated fats because they have almost the same amount of hydrogen atoms as saturated fats have.
c) trans fats are unsaturated because they have one or more double bonds, but they have physical characteristics similar to saturated fats due to the trans double bond that straightens the hydrocarbon chain.
d) trans fats are unsaturated because they have one double bond, but they have physical characteristics similar to saturated fats because they have only one double bond, which cannot change the physical characteristics signific

C)

Explanation:

The fats can be saturated or unsaturated. Saturated fats have only simple bonds between atoms of carbon. The unsaturated fats have one or more double bonds between atoms of carbon.

When there are double bonds in the carbon chain, the molecule can have geometric isometric, if the carbons of the double bond have different binders. The isomers are named cis and trans. The cis molecule has the equivalent atoms or structures (the same or mass equivalent) on the same side of the plan of the molecule. The trans molecule has this equivalent atoms or structures in the opposite side of the plan of the molecule (see figure below)

It happens in a way to stabilize the molecule. So, the trans fat, because of its disposition, has straightened the hydrocarbon chain, almost like the saturated molecule, then, they have similar characteristics.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole