Consider that a sample of a compound is decomposed and the masses of its constituent elements is as follows: 1.443 g se, 0.5848 g o what would be the empirical formula for this compound?

The empirical formula is .

Explanation:

So, the mass of each element is given:

Mass of Se = 1.443 g

Mass of O = 0.5848 g

Step 1 : convert given masses into moles.

Moles of Se=

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Se =

For O =

The ratio of Se: O = 1: 2

Hence the empirical formula is .

- lead + phosphoric acid = hydrogen + lead(ii) phosphate