(you and explain! ) here are two questions:
"the most common form of nylon (nylon-6) is 63.68% carbon, 12.38% nitrogen, 9.8% hydrogen, and 14.14% oxygen. calculate the empirical formula for nylon-6."
"there are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with oxygen gas escaping into the atmosphere while leaving a residue of pure mercury. heating 0.6498 g of one of the compounds leaves a residue of 0.6018 g. heating 4.172 g of the other compound results in a mass loss of 0.016 g. determine the empirical formula of each compound."
you for your !

The answer for the first problem is:  C₆N₁H₁₁O₁ or C₆NH₁₁O

Explanation:

Nylon composition:                     Mass        Divide by the atomic mass

Carbon                   63.68 %      63.68 g         63.68/ 12    = 5.3

Nitrogen                 12.38 %       12.38 g          12.38/14     = 0.88

Hydrogen                  9.8%           9.8 g           9.8/1           = 9.8

Oxygen                    14.14%         14.14 g          14.14/16      = 0.88

We choose the lowest number that is 0.88 for nitrogen and oxygen and divide the four results by this number

Carbon     5.3/0.88 = 6

Nitrogen    0.88/0.88 = 1

Hydrogen   9.8/0.88 = 11.1  = 11

Oxygen     0.88/ 0.88 = 1  

Then the empirical formula has this coefficients

        C₆N₁H₁₁O₁ or C₆NH₁₁O

the answer is b. dilution

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.